PHP link form mysql

<?php
$con = mysql_connect("localhost","username","password");

mysql_select_db("arrow", $con);
$result = mysql_query("SELECT * FROM phoneinfo");
echo'<select name="somename">';
while($row = mysql_fetch_array($result))
{
   
  
    echo '<option value="'.$row['mmodel'].'">'.$row['mmodel'].'</option>';
    }
    echo '</select>';?>
   
    </form>